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Question about malloc() and PIC18F6621

 
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Hans Wedemeyer



Joined: 15 Sep 2003
Posts: 226

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Question about malloc() and PIC18F6621
PostPosted: Sun May 30, 2004 7:58 pm     Reply with quote

malloc() fails to allocate 556 bytes.

The PIC18F6621 has 3840 byte of SRAM.
The project LST file shows plenty of memory available:

RAM used: 1039 (27%) at main() level
1214 (32%) worst case

I think I'm setting up correctly for using Malloc(0

From the project header file:
#include <18F6621.h>
#device *=16, adc=8
#pragma USE DYNAMIC_MEMORY
#include <STDLIBM.H>

In the help file for Malloc() the size parameter is stated to be an Integer !

Does anyone know if malloc is really limited to 255 bytes ?


from help file:
Parameters:
size is an integer representing the number of bytes to be allocated.
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Reply from CCS tech support....
PostPosted: Tue Jun 01, 2004 5:08 pm     Reply with quote

Change size_t variable in stddef.h to a long instead of an int. The malloc function uses the size_t variable to determine the return type.
Thanks
CCS Tech Support
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