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How to convert float to long?

 
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tomasch



Joined: 14 May 2004
Posts: 3

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How to convert float to long?
PostPosted: Wed May 19, 2004 9:26 pm     Reply with quote

I have a 7 segment LED display routine that requires a long (16bits) data type.

I have to do some fancy calculations that require float. I know how to cast up to float but how do you "cast down"

I have tried the following...

float x=12.34
long y

both y=x and y=(long) x give y a value of 0 (zero)

Any ideas?

Thanks in Advance

Tom
rwyoung



Joined: 12 Nov 2003
Posts: 563
Location: Lawrence, KS USA

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PostPosted: Thu May 20, 2004 7:21 am     Reply with quote

What are you expecting "y" to be in your example?

An assignment operation should make y=12 (truncation). If it is coming back as zero there may be a compiler bug so I'll ask the 64 cent question, what version of compiler are you using?
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Rob Young
The Screw-Up Fairy may just visit you but he has crashed on my couch for the last month!
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PostPosted: Thu May 20, 2004 8:03 am     Reply with quote

I'm expecting y=12 and it's 0

Version is CCS v 3.112 (I think! - How do I verify)
rnielsen



Joined: 23 Sep 2003
Posts: 852
Location: Utah

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PostPosted: Thu May 20, 2004 8:12 am     Reply with quote

Select 'Help' on the menu bar and then 'About'. This will tell you which version you have.
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PostPosted: Thu May 20, 2004 9:33 am     Reply with quote

Using the PCM version - in looking at some of the files in the directory - it's 3.112
rwyoung



Joined: 12 Nov 2003
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PostPosted: Thu May 20, 2004 7:03 pm     Reply with quote

You probably don't want to hear this but I think it is a compiler bug.

Try being a little more specific with your variable declarations:

Code:

float x=12.34;
signed long int y; // or "unsigned" instead of "signed", just be consistant with the cast later

y = (signed long int)x;


See if that helps.
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Rob Young
The Screw-Up Fairy may just visit you but he has crashed on my couch for the last month!
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