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LCD Do not initialize using PORTs A and E.
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temtronic



Joined: 01 Jul 2010
Posts: 5742
Location: Greensville,Ontario

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PostPosted: Wed Oct 18, 2017 2:28 pm     Reply with quote

Try looking up 'bit_set()' in the manual. If you press F11 while your project is open, the CCS manual 'magically' comes alive !! I usually keep it open as I can make quick reference to it. I'm lousy at C syntax being an 'assembler guy' for 40 years...
jacktaylor



Joined: 02 Sep 2017
Posts: 41

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Thank you Ttemtronic
PostPosted: Thu Oct 19, 2017 10:42 am     Reply with quote

OK thank you. Actually the synthesis confuses because there are many commands.
So in the instruction
char bitest1 = 0x00;
  if (! input (plus)) bit_set (control1,2);
We are setting 1 in bit 2 of the control variable, when ! Input (plus)

As I verify in the expression if (! Input (adj_watch)) && control1.2 == 1) that the bit2 of the variable control, really is in 1?

I know that the expression control1.2 == 1 is wrong.

I then used the expression:

if (! input (adj_watch)) && bit_test (control, 0)

but when compiling the error is generated: "A numeric expression must appear here".

using the expression:

if (! input (adj_watch)) & bit_test (control, 0)

The following error is generated when compiling the error: "Variable not permited here"
Ttelmah



Joined: 11 Mar 2010
Posts: 12507

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PostPosted: Thu Oct 19, 2017 11:47 am     Reply with quote

There are problems with your brackets.

if (! input (adj_watch)) This is the end of the if statement as posted.....

& bit_test (control, 0 This bit is trying to execute a separate operation as a result of the 'if', with only one value fed into a mathematical operation requiring two values....

Hence the errors.

if ((! input (adj_watch)) && bit_test (control, 0))

Compiles without errors.
jacktaylor



Joined: 02 Sep 2017
Posts: 41

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Thank you Ttemtronic
PostPosted: Thu Oct 19, 2017 9:16 pm     Reply with quote

Again I am very grateful for your help and explanation Ttelmah. Thank you.

Wink Smile
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