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kmp84



Joined: 02 Feb 2010
Posts: 345

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PostPosted: Thu Apr 01, 2021 9:34 am     Reply with quote
Hi mr.Ttelmah,

Thanks for help! Now it's OK.

I've added this line "timeT->month -= 1;", but I don't know porpose of this "timeT->month %= 12;" and this :

Code:

    #ifdef TIME_T_USES_2010
            i = 110;
     #else
            i = 70;
     #endif


Last my code:
Code:

time_t mktime(rtc_time_t *timeT){
   
   time_t unixTime = 0;
   int1 isLeapYear = FALSE;
   unsigned int16 i = 0;
   unsigned int16 tmp_year;

   tmp_year = 2000+timeT->year;
   timeT->month -= 1;   

   if(timeT != '\0'){
   
      unixTime += timeT->second;
      unixTime += (unsigned int32)(timeT->minute) * 60;
      unixTime += (unsigned int32)(timeT->hour) * 3600;

      isLeapYear = LeapYear(tmp_year);
       /* Clamp the month to [0,11) */
      //timeT->month %= 12;
      for(i=1; i<=timeT->month; i++)
      {
         unixTime += (DaysInMonth(i - 1, isLeapYear) * 86400);
      }

      /* Clamp the days in the month */
      //timeT->tm_mday %= DaysInMonth(timeT->tm_mon,isLeapYear);
      unixTime += (timeT->dayOfMonth - 1) * 86400;

      #ifdef TIME_T_USES_2010
         i = 110;
      #else
         i = 70;
      #endif

      while(i < tmp_year){
            
       isLeapYear = LeapYear(i);
       if(isLeapYear)
            unixTime += (31622400); // seconds in 366 days
       else
            unixTime += (31536000); // seconds in 365 days

       i++;
      }   
   }

   return unixTime;
}
Ttelmah



Joined: 11 Mar 2010
Posts: 19216

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PostPosted: Thu Apr 01, 2021 9:54 am     Reply with quote
It's the offset from 1900.
70 for 1970 based or 110 for 2010 based.
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