How to I convert a 16 bit number to two 8 bit?

[Michael Sheedy]

I am using a 16F872 10 bit ADC. I am storing the 10 bit number into a 16 bit register. How do I break the 16 bit number into 2 8 bit numbers so I can individually manipulate each byte?

Thanks in advance

Michael
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This message was ported from CCS's old forum
Original Post ID: 958

[Justin Dobbs]

Michael,

int16 big_number;
int8 high_byte;
int8 low_byte;

big_number=get_reading();
low_byte=big_number & 0xff;
high_byte=big_number>>8;

not sure if this is more efficient or not:

big_number=get_reading();
low_byte=big_number&0xff;
big_number>>=8;
high_byte=big_number;

Justin Dobbs

:=I am using a 16F872 10 bit ADC. I am storing the 10 bit number into a 16 bit register. How do I break the 16 bit number into 2 8 bit numbers so I can individually manipulate each byte?
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This message was ported from CCS's old forum
Original Post ID: 963

[Tomi]

Without arithmetics you can use the #byte directive:

int16 value;
#byte valueL = value
#byte valueH = value+1

Usage (example):
putchar(valueL); // send over RS232
putchar(valueH);

:=I am using a 16F872 10 bit ADC. I am storing the 10 bit number into a 16 bit register. How do I break the 16 bit number into 2 8 bit numbers so I can individually manipulate each byte?
:=
:=Thanks in advance
:=
:=Michael
___________________________
This message was ported from CCS's old forum
Original Post ID: 967