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azmi42
Joined: 06 Oct 2020
Posts: 9
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| PIC18LF25K40 Sleep Mode High Current Problem |
 Posted: Wed Oct 07, 2020 7:37 am |
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Hi!
In my project, in the sleep mode part, I applied everything for the extreme low-power I applied everything same as the datasheet.(You can see this part below.)
Although I have applied the same things, I drew very very very high current in the sleep mode.
My CCS C İDE 5.0089.
eXtreme Low-Power (XLP) Features
• Sleep mode: 50 nA @ 1.8V, typical
• Windowed Watchdog Timer: 500 nA @ 1.8V, typical
• Secondary Oscillator: 500 nA @ 32 kHz
• Operating Current:
– 8 uA @ 32 kHz, 1.8V, typical
– 32 uA/MHz @ 1.8V, typical
My project code is:
| Code: |
#include <18LF25K40.h> //PIC 8bits
#device ADC=10
#use delay(internal=4000000)
#FUSES PUT
#FUSES PROTECT
#FUSES NODEBUG
#FUSES NOBROWNOUT
#FUSES NOLVP
#FUSES NOCPD
#FUSES NOWRT
#FUSES NOMCLR
#fuses NOEXTOSC
#fuses RSTOSC_LFINTRC
#FUSES NOCLKOUT
#FUSES NOMCLR
void main(){
setup_oscillator(OSC_HFINTRC_4MHZ|OSC_HFINTRC_ENABLED);
setup_spi(SPI_SS_DISABLED);
setup_timer_0(T0_OFF);
setup_timer_1(T1_DISABLED);
setup_timer_2(T2_DISABLED,0,1);
setup_ccp1(CCP_OFF);
//setup_spi(SPI_MASTER|SPI_L_TO_H|SPI_XMIT_L_TO_H|SPI_CLK_DIV_4 );
while(true)
{
delay_ms(10);
sleep(SLEEP_FULL);
}
} |
If you have any ideas for this problem, please tell me.
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Ttelmah
Joined: 11 Mar 2010
Posts: 19260
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| Posted: Wed Oct 07, 2020 8:18 am |
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First little thing:
setup_spi(SPI_SS_DISABLED);
Wrong. This enables the SPI, with slave select disabled. To disable the
SPI just use
setup_spi(FALSE);
Then what is driving the PIC pins?.
No pin should ever be left floating. They must all be either pulled up/down
externally to the chip, or driven high/low by the PIC. Each floating pin,
depending on how much RF noise is around the chip can/will result in uA
more current being drawn. The pins must (obviously) be driving in the
direction that turns things 'off'.
Then the low power mode requires clocking off the low frequency
oscillator, not the 4MHz oscillator. Before sleeping, you need to
switch to this oscillator, and then switch back to the 4MHz oscillator
when you wake.
Then the XLP figure quoted is with everything turned off. You have the
WDT running, so this draws extra power etc. etc.. |
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gaugeguy
Joined: 05 Apr 2011
Posts: 290
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| Posted: Wed Oct 07, 2020 9:24 am |
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| I don't see where you show your supply voltage, measured current, method of measuring current, and power supply type. |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19260
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| Posted: Thu Oct 08, 2020 12:55 am |
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and (of course), the old common 'classic', reading current from a supply
that has a voltage regulator feeding the PIC. A typical Vreg, will often
draw several mA itself..... |
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azmi42
Joined: 06 Oct 2020
Posts: 9
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| PIC18LF25K40 Sleep Mode High Current Problem |
| Posted: Thu Oct 08, 2020 2:29 am |
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| gaugeguy wrote: | | I don't see where you show your supply voltage, measured current, method of measuring current, and power supply type. |
With the same measurement technique, 18f45k20 draws 1.5 uA in sleep mode with two batteries but 18f25k40, 18F25Q10 draws 0.475uA ~ 0.500 uA in sleep mode
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software electronic development |
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azmi42
Joined: 06 Oct 2020
Posts: 9
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| PIC18LF25K40 Sleep Mode High Current Problem |
| Posted: Thu Oct 08, 2020 2:31 am |
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| Ttelmah wrote: | First little thing:
setup_spi(SPI_SS_DISABLED);
Wrong. This enables the SPI, with slave select disabled. To disable the
SPI just use
setup_spi(FALSE);
Then what is driving the PIC pins?.
No pin should ever be left floating. They must all be either pulled up/down
externally to the chip, or driven high/low by the PIC. Each floating pin,
depending on how much RF noise is around the chip can/will result in uA
more current being drawn. The pins must (obviously) be driving in the
direction that turns things 'off'.
Then the low power mode requires clocking off the low frequency
oscillator, not the 4MHz oscillator. Before sleeping, you need to
switch to this oscillator, and then switch back to the 4MHz oscillator
when you wake.
Then the XLP figure quoted is with everything turned off. You have the
WDT running, so this draws extra power etc. etc.. |
| Code: | #include <18LF25K40.h> //PIC 8bits
#device ADC=10
#use delay(internal=4000000)
#FUSES PUT
#FUSES PROTECT
#FUSES NODEBUG
#FUSES NOBROWNOUT
#FUSES NOLVP
#FUSES NOCPD
#FUSES NOWRT
#FUSES NOMCLR
#fuses NOEXTOSC
#FUSES NOCLKOUT
#FUSES NOMCLR
void main(){
setup_oscillator(OSC_SOSC) ;
setup_timer_0(T0_OFF);
setup_timer_1(T1_DISABLED);
setup_timer_2(T2_DISABLED,0,1);
setup_timer_3(T3_DISABLED);
setup_timer_4(T4_DISABLED,0,1);
setup_timer_5(T5_DISABLED);
setup_timer_6(T6_DISABLED,0,1);
setup_vref(FALSE);
setup_ccp1(CCP_OFF);
setup_dac(DAC_OFF);
SETUP_ADC(ADC_OFF);
SETUP_ADC_PORTS(NO_ANALOGS);
DISABLE_INTERRUPTS(GLOBAL);
setup_spi(SPI_DISABLED );
set_tris_a(0x00);
set_tris_b(0x00);
set_tris_c(0x00);
set_tris_e(0x00);
OUTPUT_a(0x00);
OUTPUT_b(0x00);
OUTPUT_c(0x00);
OUTPUT_e(0x00);
while(true)
{
DELAY_MS(100);
SLEEP(SLEEP_FULL);
}
} |
peripheral pins I turned everything off but the result has not changed where am I making a mistake?
Why 18f25k40 and 18f25q10 have problems while 1845k20 is no problem
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Last edited by azmi42 on Thu Oct 08, 2020 4:49 am; edited 1 time in total |
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azmi42
Joined: 06 Oct 2020
Posts: 9
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| Posted: Thu Oct 08, 2020 2:33 am |
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| Ttelmah wrote: | and (of course), the old common 'classic', reading current from a supply
that has a voltage regulator feeding the PIC. A typical Vreg, will often
draw several mA itself..... |
I feed directly with 2 alcaline cell batteries at 3.2 volts.
_________________
software electronic development |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19260
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| Posted: Thu Oct 08, 2020 3:33 am |
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| You still haven't turned the clock rate down. |
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azmi42
Joined: 06 Oct 2020
Posts: 9
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| Posted: Thu Oct 08, 2020 4:04 am |
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| Ttelmah wrote: | | You still haven't turned the clock rate down. |
I set the oscillator clock at 32khz and tried many assumptions but the lowest I saw is 180 uA@1.8 uA
PIC18F45K20 current draw in 4Mhz oscillator 1.5uA @ 3.2v
4Mhz oscillator PIC18F25K40 current draw 500uA @ 3.2v
Where am I doing wrong I could not find :(
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software electronic development |
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gaugeguy
Joined: 05 Apr 2011
Posts: 290
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| Posted: Thu Oct 08, 2020 6:19 am |
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| Quote: | | With the same measurement technique, 18f45k20 draws 1.5 uA in sleep mode with two batteries but 18f25k40, 18F25Q10 draws 0.475uA ~ 0.500 uA in sleep mode |
It would seem from the above statement the k40 draws 1/3 the current that the k20 does.
If the above units are incorrect and you were drawing 0.5mA (instead of uA) then I suspect you are not staying in sleep. Something is waking the processor from sleep shortly after you enter. It may be the watchdog timer or another peripheral.
Set a pin high (or turn an LED on) at the beginning of your delay_ms(100) statement and then set it low at the end. Activity on this pin will determine if it is staying in sleep or not. |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19260
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| Posted: Thu Oct 08, 2020 6:27 am |
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One big difference is the default watchdog period is much faster on this chip.
Just 1mSec. Since the watchdog is not being reset anywhere, it'll be
rebooting on the watchdog, before the sleep is ever reached.... |
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temtronic
Joined: 01 Jul 2010
Posts: 9134
Location: Greensville,Ontario
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| Posted: Thu Oct 08, 2020 6:33 am |
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re: | Quote: | | I drew very very very high current in the sleep mode. |
I must be ANCIENT....as I don't see 1.5 microamps as being 'very,very high current'. 
I would though, put a recording scope/meter on to measure actual curent being drawn for say 1/2-1 hr period, then playback the events to see if current is steady or 'pulses'. My guess is 'something' is waking up the PIC. |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19260
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| Posted: Thu Oct 08, 2020 6:45 am |
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I don't think it ever reaches the sleep.
Default 1mSec. 500mSec delay. Result, reset before the sleep is reached... |
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azmi42
Joined: 06 Oct 2020
Posts: 9
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| Posted: Sat Oct 10, 2020 7:24 am |
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| Ttelmah wrote: | One big difference is the default watchdog period is much faster on this chip.
Just 1mSec. Since the watchdog is not being reset anywhere, it'll be
rebooting on the watchdog, before the sleep is ever reached.... |
Thank you so much I have solved the problem 😊
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