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		| kind2011 
 
 
 Joined: 09 Dec 2012
 Posts: 3
 
 
 
			    
 
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				| problem with pwm |  
				|  Posted: Sun Dec 09, 2012 5:16 pm |   |  
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				| I have a simple  code that I expect to generate a pwm with 11khz and 50% duty but isn't, it only works when I change the timer setup for: 
  	  | Code: |  	  | setup_timer_2(T2_DIV_BY_16,244,1); | 
 It generates a a 2.77khz wave but when I change for:
 
  	  | Code: |  	  | setup_timer_2(T2_DIV_BY_16,68,1); | 
 nothing happens at the ccp1 output?
 
  	  | Code: |  	  | #include <18F4550.h>
 #device adc=10
 #fuses HSPLL,WDT,NOPROTECT,NOLVP,NODEBUG,USBDIV,PLL5,CPUDIV1,VREGEN, PUT
 #use delay(clock=48000000)
 
 #include <usb_bootloader.h>
 #USE FAST_IO (ALL)
 #use rs232(baud=9600,xmit=PIN_C6,rcv=PIN_C7)
 
 int i=0,data;
 
 #int_timer2
 void timer2_isr(void)
 {
 set_pwm1_duty(data);
 }
 
 void main(){
 SET_TRIS_C( 0X00 );
 setup_ccp1(CCP_PWM);
 setup_timer_2(T2_DIV_BY_16,68,1);
 clear_interrupt(INT_TIMER2);
 enable_interrupts(INT_TIMER2);
 enable_interrupts(GLOBAL);
 set_pwm1_duty(data);
 while(1);
 }
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		| PCM programmer 
 
 
 Joined: 06 Sep 2003
 Posts: 21708
 
 
 
			    
 
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		| Mike Walne 
 
 
 Joined: 19 Feb 2004
 Posts: 1785
 Location: Boston Spa UK
 
 
			    
 
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				|  Posted: Sun Dec 09, 2012 5:49 pm |   |  
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				| Is your code supposed to be complete and compilable? How are you calculating the divisor to get the frequency you expect?
 Where does the 'data' value come from to set the duty ratio?
 
 Mike
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		| kind2011 
 
 
 Joined: 09 Dec 2012
 Posts: 3
 
 
 
			    
 
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				|  Posted: Sun Dec 09, 2012 9:54 pm |   |  
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				| I forgot to set the duty, this is the complete code and compilable:
 
  	  | Code: |  	  | #include <18F4550.h>
 #device adc=10
 #fuses HSPLL,WDT,NOPROTECT,NOLVP,NODEBUG,USBDIV,PLL5,CPUDIV1,VREGEN, PUT
 #use delay(clock=48000000)
 #include <usb_bootloader.h>
 #USE FAST_IO (ALL)
 #use rs232(baud=9600,xmit=PIN_C6,rcv=PIN_C7)
 
 unsigned int16 data;
 
 #int_timer2
 void timer2_isr(void)
 {
 set_pwm1_duty(data);
 }
 
 void main(){
 SET_TRIS_C( 0X00 );
 setup_ccp1(CCP_PWM);
 setup_timer_2(T2_DIV_BY_16,244,1);
 clear_interrupt(INT_TIMER2);
 enable_interrupts(INT_TIMER2);
 enable_interrupts(GLOBAL);
 
 data=511;
 set_pwm1_duty(data);
 while(1);
 }
 
 | 
 With this formula:
 The cycle time will be (1/clock)*4*t2div*(period+1)
 with a clock of 48Mhz for a cycle time of 92.5us , then  period =68
 then changing to:
 
  	  | Code: |  	  | setup_timer_2(T2_DIV_BY_16,68,1); 
 | 
 only see a line, not a pwm signal.
 Then I noticed that changing period to 200 the duty=60 and period 180 duty=70 then period of 160 and duty=79. From that I think with a period of 68 the duty is 100 but why, if I am not changing the duty?
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		| PCM programmer 
 
 
 Joined: 06 Sep 2003
 Posts: 21708
 
 
 
			    
 
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		|  |  
		| Mike Walne 
 
 
 Joined: 19 Feb 2004
 Posts: 1785
 Location: Boston Spa UK
 
 
			    
 
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				|  Posted: Mon Dec 10, 2012 1:12 pm |   |  
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				|  	  | Quote: |  	  | Then I noticed that changing period to 200 the duty=60 and period 180 duty=70 then period of 160 and duty=79. From that I think with a period of 68 the duty is 100 but why, if I am not changing the duty | 
 
 You're setting the duty to a fixed 10bit 511 value.
 
 When you set the period with:-
 
 1) An 8bit 200 value; the duty ratio is 511/(4*200) = 0,63875 approx 60%
 2) An 8bit 180 value; the duty ratio is 511/(4*180) = 0,70972 approx 70%
 3) An 8bit 160 value; the duty ratio is 511/(4*160) = 0,79844 approx 80%
 
 You're changing the PWM total period with a fixed ON period, so the DUTY RATIO changes.
 
 Mike
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		| kind2011 
 
 
 Joined: 09 Dec 2012
 Posts: 3
 
 
 
			    
 
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				|  Posted: Tue Dec 11, 2012 4:16 pm |   |  
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				| Thanks! there's a way to change the period of pwm without changing the duty ?
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		| Mike Walne 
 
 
 Joined: 19 Feb 2004
 Posts: 1785
 Location: Boston Spa UK
 
 
			    
 
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				|  Posted: Tue Dec 11, 2012 5:31 pm |   |  
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				| Kindly rephrase this question As it stands it makes no sense. 	  | Quote: |  	  | there's a way to change the period of pwm without changing the duty ? | 
 
 You need to clearly understand the basic terms.
 
 The PWM_period is set by
 where the 244 is the (PWM_period-1). 	  | Code: |  	  | setup_timer_2(T2_DIV_BY_16,244,1); | 
 
 The duty_period is set by
 where 'data' is the duty_period. 	  | Code: |  	  | set_pwm1_duty(data); | 
 
 Assuming that 'data' is 16bit, the duty ratio is given by:-
 
 duty_ratio = duty_period / (4 * PWM_period)
 
 So now, what is your question?
 
 Mike
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