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Using 2D array float type as parameters in a function

 
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rigomm



Joined: 17 Mar 2010
Posts: 13

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Using 2D array float type as parameters in a function
PostPosted: Wed Oct 20, 2010 5:09 am     Reply with quote

Hi! I did a simple program using arrays This will be the base of a more complex one.

I’m using 2D arrays and passing them as parameters into a function.

If the variables (arrays) are declared as INTEGERS, the program works perfect!
If I declare the arrays as float, the function simply cannot load the variables. I mean, the variables in the function become zero.

Below the code of both versions

USING INTEGERS
Code:

#include  "30f3012.h"                                //DEVICE
#device adc=12
//*****************CHANGED INITAL dsPIC parameter to work at higher speed using the PLL
#FUSES HS2_PLL8//The xtal freq is divided by 2 and multiplied by 8 (maximum using 20MHz xtal)
#FUSES NOWDT // NO Watch Dog Timer
#FUSES PR_PLL //Primary Oscillator
#FUSES NOCKSFSM //Clock Switching is disabled, fail Safe clock monitor is disabled
#FUSES NOPROTECT //Code not protected from reading
#FUSES NOWRT //Program memory not write protected
#use delay(clock=80000000)// 20MHz/2*8=80MHz=80000000
#use rs232(baud=115200, xmit=PIN_B4, rcv=PIN_B5)    //To transmite result over Bluetooth module
//********************************
#define LED     PIN_D0
//=========================================================

int bandpass(int r[1][2],int r2[1][2]);
//**************************************************************************************
//////////////////
//*****MAIN*****//
//////////////////
void main()
{   
   printf ("start");   
  int step = 0;
  int x[1][2]={1,2};
  int y[1][2]={3,4};
  int a[1][2]={0,0};

   while(1)
   {
      step = bandpass(x,y);
      a[0][1]=step+y[0][1] ;
      printf("  Value  %d \n \r", a[0][1]); //display
      delay_ms(1000);
   }
}   
//=====================================================
int bandpass( int r[1][2] , int r2[1][2] )
{
    int z=1;                //
    z = r[0][0];              //
    printf("  Z  %d \n \r", z); //display
    return z;
}


Using integers: Z=2; Value=6 That is correct.

USING FLOATING TYPE
Code:

#include  "30f3012.h"                                //DEVICE
#device adc=12
//*****************CHANGED INITAL dsPIC parameter to work at higher speed using the PLL
#FUSES HS2_PLL8//The xtal freq is divided by 2 and multiplied by 8 (maximum using 20MHz xtal)
#FUSES NOWDT // NO Watch Dog Timer
#FUSES PR_PLL //Primary Oscillator
#FUSES NOCKSFSM //Clock Switching is disabled, fail Safe clock monitor is disabled
#FUSES NOPROTECT //Code not protected from reading
#FUSES NOWRT //Program memory not write protected
#use delay(clock=80000000)// 20MHz/2*8=80MHz=80000000
#use rs232(baud=115200, xmit=PIN_B4, rcv=PIN_B5)    //To transmite result over Bluetooth module
//********************************
#define LED     PIN_D0
//=========================================================

float bandpass(float r[1][2],float r2[1][2]);
//**************************************************************************************
//////////////////
//*****MAIN*****//
//////////////////
void main()
{   
   printf ("start");   
  float step = 0;
  float x[1][2]={1,2};
  float y[1][2]={3,4};
  float a[1][2]={0,0};

   while(1)
   {
      step = bandpass(x,y);
      a[0][1]=step+y[0][1] ;
      printf("  Value  %f \n \r", a[0][1]); //display
      delay_ms(1000);
   }
}   
//=====================================================
float bandpass( float r[1][2] , float r2[1][2] )
{
    float z=1;                //
    z = r[0][0];              //
    printf("  Z  %f \n \r", z); //display
    return z;
}


Using float type
Z=0, Value =4 That is incorrect.

Is not possible to use float type arrays as arguments in a function?
There is a way to make it work?
Please, any idea is welcome!
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