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Problems with Printf

 
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chriss2000
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Problems with Printf
PostPosted: Tue Feb 04, 2003 6:03 am     Reply with quote

I want to printf an int16 variable on rs232

In this Code i shift my Values i read from PIN A0 in the int16 "code"
and i want to printf this int16
how can i make this ??

while(i<14)
{
while(get_timer0() >= abtast)
{
newbit=input(PIN_A0);

if(newbit == 0)
{
code=code|0x01;
code<<=1; }
if(newbit == 1)
{
code=code|0x01;
code<<=1; }
abtast=abtast+14;
i++;
}
}
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Original Post ID: 11263
PCM programmer



Joined: 06 Sep 2003
Posts: 20136

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Re: Problems with Printf
PostPosted: Wed Feb 05, 2003 2:38 pm     Reply with quote

<font face="Courier New" size=-1>:=I want to printf an int16 variable on rs232
:=
-------------------------------------------------
Chris,
If you just want to print a 16 bit value with printf,
you should do this:

main()
{
int16 code;

code = 0x55AA;

printf("code = \%lx \n\r", code);


while(1); // Prevent PIC from going to sleep (Very important)

// Extra notes on the "while(1);" line above:
// CCS puts a hidden sleep instruction after the end of main().
// The while(1) statement prevents the program from reaching
// that instruction. If it did reach that instruction, then
// the last 2 characters of your printf statement (the "AA")
// would not be displayed. So it's very important to put
// that statement above the end of main().

}


On your terminal window, you will see this:

code = 55AA

The number is displayed in hexadecimal notation.
This is caused by using "lx", which means to display
a 16-bit number in hex. To display it in unsigned
decimal format, use "lu" instead.</font>
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Original Post ID: 11311
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