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Question about CLC, PIC16F1619

 
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andresteff



Joined: 21 Mar 2020
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Question about CLC, PIC16F1619
PostPosted: Thu Jan 14, 2021 4:05 pm     Reply with quote

Hey, i have a question about the clc unit.
I use the PIC 16LF1619.

In the ccs compiler i can't find a command to connect or not connected the 4 inputs individually to the gate.

On page 447 of the datasheet it says, the pins can be connected or not connected.
The corresponding register: CLCxGLS0: GATE 1 LOGIC SELECT REGISTER.

many greetings
temtronic



Joined: 01 Jul 2010
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PostPosted: Thu Jan 14, 2021 4:41 pm     Reply with quote

I opened the manual (F11 as I use MPLAB...) and put 'CLC' in the search box.
There were 4 entries !
Now if this doesn't work for you, you may have an older version of the compiler.
This thread has got me curious to see if I can use the CLC module to replace a 30 year old PAL device.....
Ttelmah



Joined: 11 Mar 2010
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PostPosted: Fri Jan 15, 2021 8:19 am     Reply with quote

The selections to the gate are done with #pin_select. There are four
input function selections CLCIN0 to CLCIN3.
So to route PIN A0 to CLCIN0, you use:
#PIN_SELECT CLCIN0=PIN_A0
etc..
If you look at table 19-1 these then become the bottom 4 options here.
The alternative is to select internal functions (so oscillator, UART etc.).
So with the pins setup if required. you use
clcx_setup_input(n, selection), where 'n' is the input number, 1 to 4, and
'selection;, is one of the header defines:
Code:

#define CLC_INPUT_CLCIN0                    0   
#define CLC_INPUT_CLCIN1                    0x01   
#define CLC_INPUT_CLCIN2                    0x02   
#define CLC_INPUT_CLCIN3                    0x03   
#define CLC_INPUT_CLC1OUT                   0x04       
#define CLC_INPUT_CLC2OUT                   0x05       
#define CLC_INPUT_CLC3OUT                   0x06         
#define CLC_INPUT_CLC4OUT                   0x07         
#define CLC_INPUT_C1OUT                     0x08         
#define CLC_INPUT_C2OUT                     0x09         
#define CLC_INPUT_COG1A                     0x0A   
#define CLC_INPUT_COG1B                     0x0B   
#define CLC_INPUT_CCP1OUT                   0x0C         
#define CLC_INPUT_CCP2OUT                   0x0D         
#define CLC_INPUT_PWM3                      0x0E           
#define CLC_INPUT_PWM4                      0x0F           
#define CLC_INPUT_SCK1                      0x10   
#define CLC_INPUT_SDO1_SDA1                 0x11
#define CLC_INPUT_NCO                       0x12
#define CLC_INPUT_ZCD                       0x13   
#define CLC_INPUT_U1TX                      0x14   
#define CLC_INPUT_U1DT                      0x15   
#define CLC_INPUT_TIMER4                    0x16   
#define CLC_INPUT_TIMER6                    0x17   
#define CLC_INPUT_TIMER0                    0x18   
#define CLC_INPUT_TIMER1                    0x19   
#define CLC_INPUT_TIMER2                    0x1A   
#define CLC_INPUT_IOCIF                     0x1B   
#define CLC_INPUT_ADCRC                     0x1C   
#define CLC_INPUT_LFINTOSC                  0x1D   
#define CLC_INPUT_HFINTOSC                  0x1E   
#define CLC_INPUT_FOSC                      0x1F 


So if you wanted to use (say) pin A0 as input 1, for CLC1, you would need:
Code:

#PIN_SELECT CLCIN0=PIN_A0

//then
clc1_setup_input(1, CLC_INPUT_CLCIN0);
andresteff



Joined: 21 Mar 2020
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CLCxGLS0: GATE 1 LOGIC SELECT REGISTER
PostPosted: Fri Jan 15, 2021 2:17 pm     Reply with quote

thanks, but my question was a different one.
Each gate has 4 inputs, for 4 different signals.

In the datasheet on page 440 (PIC16F1619) it says:

"Enable the chosen inputs through the four gates
using CLCxGLS0, CLCxGLS1, CLCxGLS2, and
CLCxGLS3 registers.
"

Each of the 4 signals of a gate can be connected or not connected.
As inverting or not inverting.
With the: CLCxGLS0: GATE 1 LOGIC SELECT REGISTER (Page 447)
I can not find a command for it!
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Fri Jan 15, 2021 6:52 pm     Reply with quote

The data sheet page that you referenced corresponds to these parameters
in the 16F1619.h file.
Quote:

/ As an alternative to the above defines any of the following can be
// OR'ed together // to enable the individual inputs to the specified gate.
#define CLC_GATE_INVERTED_INPUT_1 0x001
#define CLC_GATE_NON_INVERTED_INPUT_1 0x002
#define CLC_GATE_INVERTED_INPUT_2 0x004
#define CLC_GATE_NON_INVERTED_INPUT_2 0x008
#define CLC_GATE_INVERTED_INPUT_3 0x010
#define CLC_GATE_NON_INVERTED_INPUT_3 0x020
#define CLC_GATE_INVERTED_INPUT_4 0x040
#define CLC_GATE_NON_INVERTED_INPUT_4 0x080
#define CLC_GATE_OUTPUT_INVERTED 0x100


So I think this is how CCS expects you to do it:
Code:

clc1_setup_gate(1, CLC_GATE_NON_INVERTED_INPUT_1 |
                   CLC_GATE_NON_INVERTED_INPUT_2 |
                   CLC_GATE_INVERTED_INPUT_3 |
                   CLC_GATE_INVERTED_INPUT_4);
Ttelmah



Joined: 11 Mar 2010
Posts: 19195

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PostPosted: Sat Jan 16, 2021 3:19 am     Reply with quote

and (of course) just omit the gate inputs that don't want a connection.
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